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leetcode 690 Employee Importance

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leetcode 690 Employee Importance

解法一

"""
# Employee info
class Employee(object):
    def __init__(self, id, importance, subordinates):
        # It's the unique id of each node.
        # unique id of this employee
        self.id = id
        # the importance value of this employee
        self.importance = importance
        # the id of direct subordinates
        self.subordinates = subordinates
"""
class Solution(object):
    def getImportance(self, employees, id):
        """
        :type employees: Employee
        :type id: int
        :rtype: int
        """
        employees = sorted(employees, key=lambda e:e.id)
        ids = [id]
        ans = 0
        for e in employees:
            if e.id in ids:
                ans += e.importance
                ids += e.subordinates
        return ans

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